How do you simplify 5sqrt8-4sqrt72+3sqrt96? Prealgebra Exponents, Radicals and Scientific Notation Square Root 1 Answer Shwetank Mauria Apr 30, 2016 5sqrt8-4sqrt72+3sqrt96=12sqrt6-14sqrt2 Explanation: 5sqrt8-4sqrt72+3sqrt96 = 5sqrt(ul(2xx2)xx2)-4sqrt(ul(2xx2)xx2xxul(3xx3))+3sqrt(ul(2xx2xx2xx2)xx2xx3) = 5xx2xxsqrt2-4xx2xx3xxsqrt2+3xx2xx2xxsqrt(2xx3) = 10sqrt2-24sqrt2+12sqrt6 = 12sqrt6-14sqrt2 Answer link Related questions How do you simplify (2sqrt2 + 2sqrt24) * sqrt3? How do you simplify sqrt735/sqrt5? How do you rationalize the denominator and simplify 1/sqrt11? How do you multiply sqrt[27b] * sqrt[3b^2L]? How do you simplify 7sqrt3 + 8sqrt3 - 2sqrt2? How do you simplify sqrt468 ? How do you simplify sqrt(48x^3) / sqrt(3xy^2)? How do you simplify sqrt ((4a^3 )/( 27b^3))? How do you simplify sqrt140? How do you simplify sqrt216? See all questions in Square Root Impact of this question 2357 views around the world You can reuse this answer Creative Commons License