How do you simplify #3sqrt50 + 5sqrt80#? Prealgebra Exponents, Radicals and Scientific Notation Square Root 1 Answer Shwetank Mauria May 24, 2017 #3sqrt50+5sqrt80=15sqrt2+20sqrt5# Explanation: #3sqrt50+5sqrt80# = #3xxsqrt(ul(5xx5)xx2)+5xxsqrt(ul(2xx2)xxul(2xx2)xx5)# = #3xx5xxsqrt2+5xx2xx2xxsqrt5# = #15sqrt2+20sqrt5# Answer link Related questions How do you simplify #(2sqrt2 + 2sqrt24) * sqrt3#? How do you simplify #sqrt735/sqrt5#? How do you rationalize the denominator and simplify #1/sqrt11#? How do you multiply #sqrt[27b] * sqrt[3b^2L]#? How do you simplify #7sqrt3 + 8sqrt3 - 2sqrt2#? How do you simplify #sqrt468 #? How do you simplify #sqrt(48x^3) / sqrt(3xy^2)#? How do you simplify # sqrt ((4a^3 )/( 27b^3))#? How do you simplify #sqrt140#? How do you simplify #sqrt216#? See all questions in Square Root Impact of this question 1897 views around the world You can reuse this answer Creative Commons License