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How do you simplify #(2y + 1 )/( y-2)#?

1 Answer

Jun 11, 2015

You can do this trick:

#(2y + 1 - 5 + 5)/(y - 2)#

#= (2y - 4 + 5)/(y-2)#

#= (2(y - 2) + 5)/(y-2)#

#= 2((y-2)/(y-2)) + 5/(y-2)#

#= 2 + 5/(y-2)#

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