How do you simplify ((2n+3)!)/((2n)!)(2n+3)!(2n)!?

1 Answer
Nov 14, 2015

((2n+3)!)/((2n)!) = (2n+3)(2n+2)(2n+1)(2n+3)!(2n)!=(2n+3)(2n+2)(2n+1)

Explanation:

((2n+3)!)/((2n)!)(2n+3)!(2n)!

color(white)("XX") = ((2n+3)xx(2n+2)xx(2n+1)xxcancel((2n))xxcancel((2n-1))xxcancel((2n-2))xx...xxcancel((1)))/(cancel((2n))xxcancel((2n-1))xxcancel((2n-2))xx...xxcancel((1)))

color(white)("XX")=((2n+3)(2n+2)(2n+1)