How do you simplify $\frac{16 x^{3}}{5 y^{9}} \cdot \frac{x^{5} y^{8}}{80 x^{3} y}$ $(16x^3)/(5y^9)*(x^5y^8)/(80x^3y)$ ?

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How do you simplify $\frac{16 x^{3}}{5 y^{9}} \cdot \frac{x^{5} y^{8}}{80 x^{3} y}$ $(16x^3)/(5y^9)*(x^5y^8)/(80x^3y)$ ?

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Answer 1 · 2016-08-09T00:01:44

$\frac{x^{5}}{25 y^{2}}$ $(x^5)/(25y^2)$

Explanation:

Simplify the numbers as for a normal fraction question. Use laws of indices to simplify the indices in the numerator and in the denominator, then simplify again for the final answer.

$(cancel16x^3)/(5y^9)*(x^5y^8)/(cancel80^5x^3y)$ =

= $(x^8y^8)/(25x^3y^10$

= $(x^5)/(25y^2)$

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How do you simplify $\frac{16 x^{3}}{5 y^{9}} \cdot \frac{x^{5} y^{8}}{80 x^{3} y}$ $(16x^3)/(5y^9)*(x^5y^8)/(80x^3y)$ ?

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How do you simplify $\frac{16 x^{3}}{5 y^{9}} \cdot \frac{x^{5} y^{8}}{80 x^{3} y}$ $(16x^3)/(5y^9)*(x^5y^8)/(80x^3y)$ ?