How do you simplify #(11x^2-22x^2)/(6x-12x^2)#?

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Answer 1 · 2015-06-28T00:53:31

Factor #11x^2# out of the numerator, and #6x# out of the denominator. Divide #x^2# by #x#. Simplify the results.

#(11x^2-22x^2)/(6x-12x^2)# =

Factor out #11x^2# from the numerator, and #6x# from the denominator.

#(11x^2(1-2))/(6x(1-2x))# =

#(11x^2(-1))/(6x(1-2x))#

Simplify.

#(-11x^2)/(6x(1-2x))#

Divide #x^2# by #x#.

#(-11xcancel(""^2))/(6cancelx(1-2x))#

Simplify .

#(-11x)/(6(1-2x))# =

#-(11x)/(6(1-2x)#