How do you multiply $\frac{8 x}{2 x + 6} \cdot \frac{x + 3}{x^{2}}$ $(8x)/(2x+6) *(x+3)/(x^2)$ ?

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Answer 1 · 2015-04-07T18:10:17

Simplify the expression
$\frac{8 x}{2 x + 6} \cdot \frac{x + 3}{x^{2}}$ $(8x)/(2x+6) * (x+3)/(x^2)$

as
$\frac{(8) (x) (x + 3)}{(2) (x + 3) (x) (x)}$ $( (8)(x)(x+3) )/((2)(x+3)(x)(x))$

$( cancel((8))^4cancel((x))cancel((x+3)) )/(cancel((2))cancel((x+3))cancel((x))(x))$

$=4/x$

How do you multiply (8x)/(2x+6) *(x+3)/(x^2)8x2x+6⋅x+3x2(8x)/(2x+6) *(x+3)/(x^2)?