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How do you integrate #xe^(x^2) dx#?

1 Answer

Aug 14, 2016

This can be done by substitution. See explanation.

Explanation:

#intxe^(x^2)dx=|(t=x^2),(dt=2xdx),(dt/2=xdx)|=int(e^t/2)dt=1/2int(e^tdt)#

#=1/2e^t+C=1/2e^(x^2)+C#

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