How do you integrate #ln(b/x)dx#? Calculus Techniques of Integration Integration by Parts 1 Answer Douglas K. Oct 25, 2016 Please see the explanation Explanation: #intln(b/x)dx =# # intln(b) - ln(x)dx =# #xln(b) - xln(x) + x + C# Answer link Related questions How do I find the integral #int(x*ln(x))dx# ? How do I find the integral #int(cos(x)/e^x)dx# ? How do I find the integral #int(x*cos(5x))dx# ? How do I find the integral #int(x*e^-x)dx# ? How do I find the integral #int(x^2*sin(pix))dx# ? How do I find the integral #intln(2x+1)dx# ? How do I find the integral #intsin^-1(x)dx# ? How do I find the integral #intarctan(4x)dx# ? How do I find the integral #intx^5*ln(x)dx# ? How do I find the integral #intx*2^xdx# ? See all questions in Integration by Parts Impact of this question 1367 views around the world You can reuse this answer Creative Commons License