How do you integrate $int xe^x dx$ using integration by parts?

Question

17797 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-09T00:41:20

$I = e^x(x - 1) + c$

$I = intxe^xdx$

Say $u = x$ so $du = 1$ , $dv = v = e^x$

$I = xe^x - inte^xdx$
$I = xe^x - e^x$
$I = e^x(x - 1) + c$

How do you integrate int xe^x dx int xe^x dx using integration by parts?