How do you integrate $int x sinx dx$ using integration by parts?

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Answer 1 · 2016-01-09T01:44:06

$I = sin(x) - xcos(x) + c$

$I = intxsin(x)dx$

Say $u = x$ so $du = 1$ and $dv = sin(x)$ so $v = -cos(x)$

$I = -xcos(x) + intcos(x)dx$
$I = sin(x) - xcos(x) + c$

How do you integrate int x sinx dx int x sinx dx using integration by parts?