How do you integrate $int x sin sqrtx dx$ using integration by parts?

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Answer 1 · 2016-01-24T14:19:10

let's $u = sqrt(x)$

$du = 1/(2sqrt(x))dx$

$2udu = dx$

$u^2=x$

so you have

$2intu^3sin(u)du$

And integrate by part three time and you have

$2[(3 (u^2-2) sin(u)-u (u^2-6) cos(u))]+C$

How do you integrate int x sin sqrtx dx int x sin sqrtx dx using integration by parts?