How do you integrate $int tcsctcott$ by parts?

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Answer 1 · 2017-02-18T16:49:54

$inttcsctcottdt = -tcsct - ln|csct + cott| + C$

Let $dv = csctcottdt$ and $u = t$ . This means that $v= -csct$ and $du = dt$ .

$intudv = uv - intvdu$

$inttcsctcottdt = t(-csct) - int(-csctdt)$

$inttcsctcottdt = -tcsct + intcsctdt$

The integral of $csct$ can be found here

$inttcsctcottdt = -tcsct - ln|csct + cott| + C$

Hopefully this helps!

How do you integrate int tcsctcottint tcsctcott by parts?