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How do you integrate #(e^x)/x#?

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A. S. Adikesavan

Feb 18, 2017

For# x > 0#,

#inte^x/x dx #

#=int (1+x+x^2/(2!)+x^3/(3!)+...)/x dx#

#=C+lnx+x/(1!)+x^2/(2(2!))+x^3/(3(3!))+...+x^n/(n((n)!))+...#

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