# How do you integrate (e^sin(x))cos(x) dx?

$\int {e}^{\sin x} \cos x \mathrm{dx} = {e}^{\sin} x$
Let $u = \sin x$, then $\mathrm{du} = \cos x \mathrm{dx}$ and
$\int {e}^{\sin x} \cos x \mathrm{dx} = \int {e}^{u} \mathrm{du} = {e}^{u} = {e}^{\sin} x$