How do you integrate by parts #(xe^x)/((x+1)^2)#? Calculus Techniques of Integration Integration by Parts 1 Answer GiĆ³ Jun 16, 2015 I found: #-(xe^x)/(x+1)+e^x+c# Explanation: Have a look: Answer link Related questions How do I find the integral #int(x*ln(x))dx# ? How do I find the integral #int(cos(x)/e^x)dx# ? How do I find the integral #int(x*cos(5x))dx# ? How do I find the integral #int(x*e^-x)dx# ? How do I find the integral #int(x^2*sin(pix))dx# ? How do I find the integral #intln(2x+1)dx# ? How do I find the integral #intsin^-1(x)dx# ? How do I find the integral #intarctan(4x)dx# ? How do I find the integral #intx^5*ln(x)dx# ? How do I find the integral #intx*2^xdx# ? See all questions in Integration by Parts Impact of this question 4280 views around the world You can reuse this answer Creative Commons License