How do you graph #y=(x+1)^2 - 4#?

1 Answer
Alan P.
Jan 21, 2016

Evaluate #y# for several values of #x#; plot the corresponding coordinate points; joint the points with as smooth a line as you can.

Explanation:

For #color(black)(y=(x+1)^2-4# I picked the points:

#{: (color(black)(x),"|",color(white)("X")color(black)(y)), ("----",,"----"), (-1,"|",-4), (color(white)("X")0,"|",-3), (-2,"|",-3), (color(white)("X")1,"|",color(white)("X")0), (-3,"|",color(white)("X")0), (color(white)("X")2,"|",color(white)("X")5), (-4,"|",color(white)("X")5) :}#
enter image source here

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