How do you graph #y=-tan(x-pi/2)+5#?

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Answer 1 · 2018-06-24T03:05:16

As below.

#y = - tan (x - pi/2) + 5#

Standard form of tangent function is #y = A tan(Bx - C) + D#

#A = -1, B = 1, C = pi/2, D = 5#

#Amplitude = |A| = "NONE" for tangent function"#

#"Period " = (pi) / |B| = (pi) / 1 = pi#

#"Phase Shift " = -C / B = pi/2 / 1 = pi/2, " " pi/2 " to the RIGHT"##

#"Vertical Shift " = D = 5#

graph{- tan(x - pi/2) + 5 [-10, 10, -5, 5]}