How do you graph $y=-tan(x-pi/2)+5$ ?

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Answer 1 · 2018-06-24T03:05:16

As below.

$y = - tan (x - pi/2) + 5$

Standard form of tangent function is $y = A tan(Bx - C) + D$

$A = -1, B = 1, C = pi/2, D = 5$

$Amplitude = |A| = "NONE" for tangent function"$

$"Period " = (pi) / |B| = (pi) / 1 = pi$

$"Phase Shift " = -C / B = pi/2 / 1 = pi/2, " " pi/2 " to the RIGHT"$ #

$"Vertical Shift " = D = 5$

graph{- tan(x - pi/2) + 5 [-10, 10, -5, 5]}

How do you graph y=-tan(x-pi/2)+5y=-tan(x-pi/2)+5?