How do you graph $y=tan((pi/2)x)$ ?

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Answer 1 · 2018-06-13T08:25:03

As below.

Standard form of tangent function is $y = A tan (Bx - C) + D$

Given : $y tan ((pi/2)x)$

$A= 1, B = pi/2, C = 0, D = 0$

$Amplitude =$ “None”

Period $= pi / |B| = (pi) / (pi/2) = 2$

Phase shift = $-C / B = 0$

Vertical shift $= D = 0$

graph{tan ((pi/2)x) [-10, 10, -5, 5]}

How do you graph y=tan((pi/2)x)y=tan((pi/2)x)?