How do you graph #y=tan((pi/2)x)#?

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Answer 1 · 2018-06-13T08:25:03

As below.

Standard form of tangent function is #y = A tan (Bx - C) + D#

Given : #y tan ((pi/2)x)#

#A= 1, B = pi/2, C = 0, D = 0#

#Amplitude = # “None”

Period # = pi / |B| = (pi) / (pi/2) = 2#

Phase shift = #-C / B = 0#

Vertical shift # = D = 0#

graph{tan ((pi/2)x) [-10, 10, -5, 5]}