How do you graph $y = tan (3 x + \frac{π}{3})$ $y =tan (3x + pi/3)$ ?

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Answer 1 · 2018-06-07T01:42:29

As below.

Standard form of Tangent function is $y = A tan (B x - C) + D$ $color(purple)(y = A tan(Bx - C)+ D$

$Given y = tan (3 x + \frac{π}{3})$ $"Given " y = tan (3x + pi/3)$

#"Amplitude " = |A| = color(green)("None") "for tangent function"

$Period = \frac{π}{| B |} = \frac{π}{3}$ $"Period " = pi / |B| = pi/3$

$Phase Shift = - \frac{C}{B} = - \frac{π}{3}, \frac{π}{3} to the left$ $"Phase Shift " = -C / B = -pi/3, color(green)(pi/3) "to the left"$

$Vertical Shift = D = 0$ $"Vertical Shift " = D = 0$

graph{tan (3x + (pi/3)) [-10, 10, -5, 5]}

How do you graph y=tan(3x+π3) y =tan (3x + pi/3)?