How do you graph $y = sin(x - π/4) + 2$ ?

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Answer 1 · 2018-06-06T12:00:13

As below.

$y = sin (x - (pi/4)) + 2$

Standard Form of a sine function is $y = A sin (Bx - C) + D$

$:. A = 1, B = 1, C = pi/4, D = 2$

$Amplitude = |A| = 1$

Period $= (2pi) / |B| = 2pi$

Phase Shift $= -C / B = pi/4$ , $pi/4$ to the right#

Vertical Shift $= D = 2$

graph{sin(x-(pi/4)) + 2 [-10, 10, -5, 5]}

How do you graph y = sin(x - π/4) + 2y = sin(x - π/4) + 2?