How do you graph $y = - sec 2 x$ $y=-sec2x$ ?

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Answer 1 · 2018-06-07T01:46:39

As below.

Standard form of Secant function is $y = A sec (B x - C) + D$ $color(violet)(y = A sec (Bx - C) + D$

$Given y = - sec (2 x)$ $"Given " y = - sec( 2x)$

$A = - 1, B = 2, C = 0, D = 0$ $A = -1, B = 2, C = 0, D = 0$

$A m p l i t u d e = None for secant function$ $Amplitude = "None for secant function"$

$Period = \frac{2 π}{| B |} = \frac{2 π}{2} = π$ $"Period " = (2pi) / |B| = (2pi)/ 2 = pi$

$Phase Shift = - \frac{C}{B} = 0$ $"Phase Shift " = -C / B = 0$

$Vertical Shift = D = 0$ $"Vertical Shift " = D = 0$

graph{-sec (2x) [-10, 10, -5, 5]}

How do you graph y=−sec2xy=-sec2x?