How do you graph #y=sec(1/2(x-pi/2))#?
1 Answer
Oct 31, 2016
graph{y=sec((1/2)(x-(pi/2))) [-14.89, 17.17, -6.56, 9.47]}
Explanation:
graph{y=sec((1/2)(x-(pi/2))) [-14.89, 17.17, -6.56, 9.47]}
This is how to graph it. Note that you need the secant graph memorized, then you just apply a vertical compression by a factor of
