How do you graph $y = csc (x - 45)$ $y=csc(x-45)$ ?

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Answer 1 · 2018-06-13T08:38:16

As below.

Standard form of cosine function is $y = A cos (B x - C) + D$ $y = A cos (Bx - C) + D$

Given : $y = csc (x - 45^{\circ})$ $y = csc (x - 45^@)$

$A = 1, B = 1, C = 45 = \frac{π}{4}$ $A = 1, B = 1, C = 45 = pi/4$

$A m p l i t u d e = | A | = N O N E f or C S C f u n c t i o n$ $Amplitude = |A| = "NONE for CSC function$

Period $= \frac{2 π}{| B |} = 2 π$ $= (2pi)/|B| = 2pi$

Phase Shift $= - \frac{C}{B} = \frac{\frac{π}{4}}{1} = \frac{π}{4}$ $= -C / B = (pi/4) / 1 = pi/4$ , $\frac{π}{4}$ $pi/4$ to the right

Vertical shift = 0

graph{csc(x - (pi/4)) [-10, 10, -5, 5]}

How do you graph y=csc(x−45)y=csc(x-45)?