How do you graph $y=csc(2*theta+π)-3$ ?

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Answer 1 · 2018-03-11T08:07:26

As below.

Standard form of equation for csc is $y = a csc (b theta - c) + d$

$y = csc (2theta + pi) - 3$

Period = (2pi) / |b| = (2pi) / 2 = pi#

Phase shift = c / b = -pi / 2 = -pi/2color(white)(aaa)pi/2# to the left.

Vertical shift $= d = - 3$

graph{csc (2x + pi) - 3 [-10, 10, -5, 5]}

How do you graph y=csc(2*theta+π)-3y=csc(2*theta+π)-3?