How do you graph $y = cot(x-pi/5)$ ?

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Answer 1 · 2018-04-09T10:54:40

As below.

y = cot(x - (pi/5)#

Standard form of equation is

$y = A cot (Bx - C) + D$

$Amplitude = A = " None" " for cotangent"$

$"Period " = pi / |B| = pi$

$"Phase Shift " = -C / B = (pi/5) / 1 = pi/5 " to the right"$

$"Vertical Shift " = D = 0$

graph{cot (x - (pi/5)) [-10, 10, -5, 5]}

How do you graph y = cot(x-pi/5)y = cot(x-pi/5)?