How do you graph y=cotx? Trigonometry Graphing Trigonometric Functions Graphing Tangent, Cotangent, Secant, and Cosecant 1 Answer sankarankalyanam Jun 28, 2018 As Below. Explanation: y=cotx Standard form is y=Acot(Bx−C)+D A=1,B=1,C=0,D=0 Amplitude=|A|=NONE for cotangent function Period =π|B|=π1=π Phase Shift =C=0 Vertical Shift =D=0 graph{cot x [-10, 10, -5, 5]} Answer link Related questions How do you find the asymptotes for the cotangent function? How do you graph tangent and cotangent functions? How do you Sketch the graph of y=−2+cot(13)x over the interval [0,6π]? How do you graph y=−3tan(x−(π4)) over the interval [−π,2π]? How do you sketch a graph of h(x)=5+12sec4x over the interval [0,2π]? What is the amplitude, period and frequency for the function y=−1+13cot2x? How do you graph y=3sec(2x)? How do you graph y=tan(2x+π4)? What is the domain of y=tan(x)+2? How do you graph csc(x−π2)? See all questions in Graphing Tangent, Cotangent, Secant, and Cosecant Impact of this question 4602 views around the world You can reuse this answer Creative Commons License