How do you graph $y=cot(theta+pi)$ ?

Question

2373 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-07T01:37:27

As Below

$color(indigo)(y = A cot (B theta - C) + D$

Given function is $y cot (theta + pi)$

#Amplitude = |A| = color(red)("None") for cotangent function

$"Period " = pi / |B| = pi$

$"Phase Shift " = - C/B = -pi, color(indigo)(pi) " to the left"$

$"vertical Shift " = D = 0$

graph{cot (x + pi) [-10, 10, -5, 5]}

How do you graph y=cot(theta+pi)y=cot(theta+pi)?