How do you graph $y = - cot (4 π x)$ $y=-cot(4pix)$ ?

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Answer 1 · 2018-06-20T04:01:07

As below.

Standard form of cotangent function is $y = A cot (B x - C) + D$ $y = A cot(Bx - C) + D$

$Given : y = - cot (4 π x)$ $"Given : " y = - cot (4pix)$

$A = - 1, B = 4 π, C = D = 0$ $A = -1, B = 4pi, C = D = 0$

$Amplitude = | A | = NONE for cotangent$ $"Amplitude " = |A| = color(crimson)("NONE ") " for cotangent"$

$Period = \frac{π}{| B |} = \frac{π}{4 π} = \frac{1}{4}$ $"Period " = pi / |B| = pi / (4 pi) = 1/4$

$Phase Shift " = - C / B = 0$

$"Vertical Shift " = D = 0$

graph{- cot (4pix) [-10, 10, -5, 5]}

How do you graph y=-cot(4pix)y=−cot(4πx)y=-cot(4pix)?