How do you graph $y=cot(2theta)$ ?

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Answer 1 · 2018-06-18T01:38:32

As detailed below.

Standard form of cotangent function is $y = A cot (Bx - C) + D$

$"Given : " y = cot (2theta)$

$A = 1, B = 2, C = D = 0$

$"Amplitude " = |A| = " NONE for cot function"$

$"Period " = pi / |B| = pi / 2$

$"Phase shift " = - C / B = 0$

$"Vertical shift " = D = 0$

graph{cot (2x) [-10, 10, -5, 5]}

How do you graph y=cot(2theta)y=cot(2theta)?