How do you graph $y+8=0$ ?

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Answer 1 · 2018-07-21T20:39:53

First, make $y$ by itself by subtracting $color(blue)8$ from both sides of the equation:
$y + 8 quadcolor(blue)(-quad8) = 0 quadcolor(blue)(-quad8)$

$y = -8$

Since there is no " $x$ " in the equation, that means that $y$ is a constant and it is always $-8$ .

Here is a graph of the line:
enter image source here
(desmos.com)

As you can see, $y$ is always $-8$ , no matter what the $x$ value is.

Hope this helps!

How do you graph y+8=0y+8=0?