How do you graph $y = 4tan3(x + pi/3) - 6$ ?

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Answer 1 · 2018-07-11T01:23:13

As Below.

Standard form of tangent function is $y = A tan (Bx - C) + D$

$"Given : " y = 4 tan (3x + pi) - 6$

$A = 4, B = 3, C = -pi, D = -6$

$Amplitude = |A| = "NONE for tangent function"$

$"Period " = pi / |B| = pi/3$

$"Phase Shift " = -C / B = -pi / 3, pi/3 " to the RIGHT"$

$"Vertical Shift " = D = -6$

graph{4 tan(3x + pi) - 6 [-10, 10, -5, 5]}

How do you graph y = 4tan3(x + pi/3) - 6y = 4tan3(x + pi/3) - 6?