How do you graph $y=4cot(1/3t)$ over the interval $[-3pi, 3pi]$ ?

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Answer 1 · 2017-03-28T16:20:19

Using a graphing calculator:
Change the function to $tan$ : $y = 4/(tan(1/3t))$

$cot theta = 1/(tan theta)$

Using a graphing calculator:
Change the function to $tan$ : $y = 4/(tan(1/3t))$

Make sure your MODE = radians.
Change your WINDOW to Xmin = $-3pi$ , Xmax = $3pi$

There are holes at $(-3pi)/2$ and $(3pi)/2$

There are vertical asymptotes at $x = 0$ and $x = -3pi$

graph{4/tan(x/3) [-10, 10, -5, 5]}

How do you graph y=4cot(1/3t)y=4cot(1/3t) over the interval [-3pi, 3pi][-3pi, 3pi]?