# How do you graph #y+4=0#?

##### 2 Answers

See a solution process below:

#### Explanation:

We can solve this for

This equation shows for each and every value of

We can find two points to plot as:

For

For

graph{(x^2+(y+4)^2-0.075)((x-5)^2+(y+4)^2-0.075)=0 [-15, 15, -7.5, 7.5]}

We can now draw a line through the two points giving:

graph{(y+4)(x^2+(y+4)^2-0.075)((x-5)^2+(y+4)^2-0.075)=0 [-15, 15, -7.5, 7.5]}

We can this is a horizontal line from

Refer to the explanation.

#### Explanation:

Graph:

Solve for

The graph will be a horizontal line at