How do you graph $y=3tan(2x+pi/2)-2$ ?

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Answer 1 · 2018-04-12T09:57:03

As below.

Standard form of equation is $y = A tan (Bx - C) + D$

Given equation is $y = 3 tan (2x + (pi/2)) -2$

$Amplitude = |A| = " None " " for tangent"$

$"Period " = pi / |B| = pi / 2$

$"Phase Shift " = (-C) / B = (-(pi/2)) / 2 = -pi/4, " " pi/4 " to the left"$

$"Vertical Shift " = D = -2$

graph{3 tan(2x + (pi/2)) - 2 [-10, 10, -5, 5]}

How do you graph y=3tan(2x+pi/2)-2y=3tan(2x+pi/2)-2?