How do you graph $y=3tan(2pit)$ over the interval $[-1/2, 1/2]$ ?

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Answer 1 · 2018-07-19T03:55:29

$y = 3 tan 2pix$ .

The period for this graph is $pi/(2pi) = 1/2$

The asymptotes are $2pix = (( 2k + 1 )(pi/2) rArr x = ( 2k + 1 )/4$

k = 0, +-1, +-2, +-3, ...#

So, the graph for $x in [ - 1/2, 1/2 ]$ is for

$x in [ -1/2, -1/4 ) U ( -1/4, 1/4) U ( 1/4, 1/2 ]$ , excluding infinite

discontinuities at $x = +- 1/4$ .

Now see graph.
graph{y-3 tan ( 2 pi x )=0[-0.5 0.5 ]} .

How do you graph y=3tan(2pit)y=3tan(2pit) over the interval [-1/2, 1/2][-1/2, 1/2]?