How do you graph $y=3csc(x+(2pi)/3)$ ?

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Answer 1 · 2018-06-07T01:23:04

As below

Standard form of cosecant function is $color(crimson)(y = A sin (Bx - C) + D$

Given $color(blue)(y = 3 csc (x + (2pi)/3)$

$:. A = 3, B = 1, C = - (2pi) / 3, D = 0$

$color(crimson)("Amplitude" = |A| =" None"$ for cosecant function.

$color(crimson)("Period " = (2pi) / |B| = 2pi)$

$color(crimson)("Phase Shift " = -C / B = -(2pi) / 3), (2pi) / 3$ "to the left".

$color(crimson)("Vertical Shift" = 0$

graph{3 csc(x + (2pi)/3) [-10, 10, -5, 5]}

How do you graph y=3csc(x+(2pi)/3)y=3csc(x+(2pi)/3)?