How do you graph #y=-3cot(1/2(x+pi))-1#?

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Answer 1 · 2018-06-16T10:01:12

As below.

#"Standard form of cotangent function " y = A cot (Bx -C) + D#

#y = -3cot graph{-3 cot(x/2 + pi/2) - 1 [-10, 10, -5, 5]} (x/2 + pi/2) -1#

#A = -3, B = 1/2, C = -pi/2, D = -1#

#Amplitude = |A| = "NONE for cotangent function"#

#"Period = pi / |B| = pi / (1/2) = 2pi#

#"Phase Shift " = -C / B = (pi/2)/(1/2) = pi, pi " to the right"#

#"Vertical Shift " = D = -1#