How do you graph #y=2tan3x#?

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Answer 1 · 2018-07-29T11:11:40

#x=(npi)/3#

To find the variables. Use the form

#atan(bx-c)+d#

This gives the following values as:-

#a=2 , b=3, c=0, d=0#

It has not stated the max. and min. value. Amplitude #=0#

Now, the period of the graph #= pi/3#

Find the parallel shift using #c/b#

This would generate the graph as:

graph{y=2tan(3x) [-10, 10, -5, 5]}