How do you graph $y=2tan(2x+pi/4)$ ?

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Answer 1 · 2017-10-05T23:19:06

$y=2tan(2x+pi/4)$
graph{2tan(2x+(pi/4)) [-10, 10, -5, 5]}

$y=a*tan(bx-c)+d$
$Amplitude$ $a=2$
$Period=pi/b=pi/2$
$Phase$ shift $=c/b=(-pi/4)/2=-pi/8=pi/8$ to the left
$Vertical$ shift $=d=0$

How do you graph y=2tan(2x+pi/4)y=2tan(2x+pi/4)?