How do you graph $y=2sin(2x+pi/2)+3$ ?

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Answer 1 · 2018-03-09T15:38:51

Amplitude $= 2$

Period $= pi$

Phase shift $= -(pi/ 4)$ $color(white)(aaa)(pi/4)$ to the left.

Vertical shift $= 3$

Standard form of equation is $y = a sin(bx + c) + d$

Given = $y = 2 sin (2x + pi/2) + 3$

Amplitude $= a = 2$

Period $= (2pi) / |b| = (2pi) / 2 = pi$

Phase shift $= - c / b = -(pi/2) / 2 = -(pi/ 4)$ $color(white)(aaa)(pi/4)$ to the left.

Vertical shift $= d = 3$

graph{2sin(2x+(pi/2))+3 [-10, 10, -5, 5]}

How do you graph y=2sin(2x+pi/2)+3y=2sin(2x+pi/2)+3?