How do you graph $y=-2sec2(x+pi)+3$ ?

Question

1889 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-16T09:53:07

As below.

$y = - 2 sec (2x + 2pi) + 3$

Standard form of secant function is $y = A sec(Bx - C) + D$

$A = -2, B = 2, C = -2pi, D = 3$

$Amplitude = |A| = "None for secant function"$

$"Period " = (2pi) / |B| = (2pi) / 2 = pi$

$"Phase Shift " = -C/B = (2pi) / 2 = pi, pi " to the right"$

$"Vertical Shift " = D = 3$

graph{-2 sec(2x + 2pi) + 3 [-10, 10, -5, 5]}

How do you graph y=-2sec2(x+pi)+3y=-2sec2(x+pi)+3?