How do you graph #y=2sec(3(x-pi/6))+1#?

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Answer 1 · 2018-06-24T02:58:39

As below.

#y = 2 sec (3x - pi/2)#

Standard form of secant function is #y = A sec(Bx - C) + D#

#A = 2, B = 3, C = -pi/2, D = 1#

#Amplitude = |A| = "NONE for secant function"#

#"Period " = (2pi) / |B| = (2pi) / 3#

#"Phase Shift " = -C / B = (pi/2) / 3 = pi/6, " " pi/6 " to the RIGHT"#

#"Vertical Shift " = D = 1#

graph{2 sec(3x - pi/2) + 1 [-10, 10, -5, 5]}