How do you graph #y=2sec(1/2)x#? Trigonometry Graphing Trigonometric Functions Graphing Tangent, Cotangent, Secant, and Cosecant 1 Answer bp Feb 26, 2016 Explained below: Explanation: The period of the function is #(2pi)/(1/2) = 4pi#. The graph would look like as shown in the figure. Answer link Related questions How do you find the asymptotes for the cotangent function? How do you graph tangent and cotangent functions? How do you Sketch the graph of #y=-2+cot(1/3)x# over the interval #[0, 6pi]#? How do you graph #y=-3tan(x-(pi/4))# over the interval #[-pi, 2pi]#? How do you sketch a graph of #h(x)=5+frac{1}{2} \sec 4x# over the interval #[0,2pi]#? What is the amplitude, period and frequency for the function #y=-1+\frac{1}{3} \cot 2x#? How do you graph #y = 3 sec(2x)#? How do you graph #y=tan(2x+pi/4)#? What is the domain of #y = tan(x) + 2#? How do you graph #csc(x-pi/2)#? See all questions in Graphing Tangent, Cotangent, Secant, and Cosecant Impact of this question 3060 views around the world You can reuse this answer Creative Commons License