How do you graph $y = 2 csc x - 1$ $y = 2cscx - 1$ ?

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Answer 1 · 2018-06-07T01:55:40

As below.

Standard form $y = A csc (B x - C) + D$ $color(blue)(y = A csc (Bx - C) + D$

Given $y = 2 csc (x) - 1$ $y = 2 csc (x ) - 1$

$A m p l i t u d e = | A | = NONE for co-secant function$ $Amplitude = |A| = color(crimson)("NONE") " for co-secant function"$

$Period = \frac{2 π}{| B |} = 2 π$ $"Period " = (2pi) / |B| = 2pi$

$Phase Shift = - \frac{C}{B} = 0$ $"Phase Shift " = -C / B = 0$

"Vertical Shift " = D = -1#

graph{2 csc(x) - 1 [-10, 10, -5, 5]}

How do you graph y=2cscx−1y = 2cscx - 1?