How do you graph $y=2csc2(x+pi)$ ?

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Answer 1 · 2018-06-24T02:55:20

As below.

$y = 2 csc (2x + 2 pi)$

Standard form of cosecant function is $y = A csc(Bx - C) + D$

$A = 2, B = 2, C = -2 pi, D = 0$

$Amplitude = |A| = "NONE for cosecant function"$

$"Period " = (2pi) / |B| = (2pi) / 2 = pi$

$"Phase Shift " = -C / B = -(2pi) / 2 = -pi, " " pi " to the LEFT"$

$"Vertical Shift " = D = 0$

graph{2 csc(2x + 2 pi) [-10, 10, -5, 5]}

How do you graph y=2csc2(x+pi)y=2csc2(x+pi)?