How do you graph y=2csc[2(x+π6)]?

1 Answer
Jun 24, 2018

As Below.

Explanation:

y=2csc(2x+π3)

Standard form of cosecant function is y=Acsc(BxC)+D

A=2,B=2,C=π3,D=0

Amplitude=|A|=NONEforcosecantfunction

Period =2π|B|=2π2=π

Phase Shift =CB=π32=π6, π6 to the LEFT

Vertical Shift =D=0

graph{2 csc(2x + pi/3) [-10, 10, -5, 5]}