How do you graph $y=2cot(x-pi/2)$ ?

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Answer 1 · 2018-04-27T12:04:25

As below:

$y = 2 cot(x - pi/2)$

Standard form is $y = A cot (Bx -C) + D$

$"Amplitude " = |A| = 2 = " None, for cot"$

$"Period " P = pi / |B| = pi / 1 = pi$

$"Phase Shift " = -C / B =( pi / 2 ) / 1 = pi/2 " to the right"$

$"Vertical Shift " = D = 0$

graph{2 cot (x - (pi/2)) [-10, 10, -5, 5]}

How do you graph y=2cot(x-pi/2)y=2cot(x-pi/2)?