How do you graph y=-2cot(2pix)?

1 Answer
A. S. Adikesavan
Aug 6, 2018

See explanation.

Explanation:

y = - 2 cot ( 2 pi x ), x ne asymptotic k/2, k = 0, +-1, +-2, +-3, ...#

The period of both tan mx and cot mx is (pi/m)_(-).

Here, the period is (pi/(2pi)) = (1/2)_(-)

See graph, revealing these aspects.
graph{(y sin(2pix)+2cos(2pix))(x-1/2+0.001y)(x+1/2+0.0001y)(x+0.0001y)=0[-1 1 -5/2 3/2]}
For better visual effect,

the graph is not on uniform scale. '1 in x' is '10 in y'.

A note on amplituse

= (1/4)_(-)

= 1/2 (spacing between two consecutive asymptotes).

Seemingly, the amplitude from the equation is 2.

You can see that this is incorrect.

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