How do you graph #y-2=8# using the slope and intercept?

1 Answer
Camilleon
Jun 6, 2018

#y = 10#

Explanation:

#y - 2 = 8#

First, you want to get your equation closest to the #y = mx + b# format as possible. To do this, we'll be solving the equation as a one step problem:

#y - 2 = 8#

Add #2# to both sides to cancel out #-2#. You should now have:

#y = 10#

Now, since this equation is on the #y#-axis, you'll be plotting your equation there. The slope is #0# in this case, and your #y#-intercept will be #(0, 10)#. Your line will be horizontal and continuous. Your graph will look like this:

graph{y = 0x + 10 [-29.34, 35.6, -4.15, 28.33]}

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